How do you solve $-2(x-1)=1-3x$ ?

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Answer 1 · 2018-05-30T10:11:22

$x = -1$

Expand the parenthesis multiplying each term inside for the constant outside:

$-2(x-1) = -2\cdot x + (-2)\cdot (-1) = -2x+2$

The equation becomes

$-2x+2 = 1-3x$

Add $3x$ to both sides:

$-2x+3x+2 = 1-3x+3x \implies x+2 = 1$

Subtract $2$ from both sides:

$x+2-2 = 1-2 \implies x = -1$

How do you solve -2(x-1)=1-3x-2(x-1)=1-3x?