How do you solve #-2(x-1)=1-3x#?

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Answer 1 · 2018-05-30T10:11:22

#x = -1#

Expand the parenthesis multiplying each term inside for the constant outside:

#-2(x-1) = -2\cdot x + (-2)\cdot (-1) = -2x+2#

The equation becomes

#-2x+2 = 1-3x#

Add #3x# to both sides:

#-2x+3x+2 = 1-3x+3x \implies x+2 = 1#

Subtract #2# from both sides:

#x+2-2 = 1-2 \implies x = -1#