How do you solve #2(x-3)=(x-1)+7#?
1 Answer
Jun 20, 2018
Explanation:
#"distribute brackets on both sides of the equation"#
#2x-6=x-1+7#
#2x-6=x+6#
#"subtract "x" from both sides"#
#2x-x-6=6#
#"add 6 to both sides"#
#x=6+6=12#
#color(blue)"As a check"# Substitute this value into the equation and if both sides are equal then it is the solution.
#"left "=2(12-3)=2xx9=18#
#"right "=(12-1)+7=11+7=18#
#x=12" is the solution"#
