How do you solve #2( x + 4) < 10#?
1 Answer
Nov 6, 2016
Explanation:
The first step is to distribute the bracket.
#rArr2x+8 < 10# subtract 8 from both sides.
#2xcancel(+8)cancel(-8) < 10-8#
#rArr2x < 2# To solve for x, divide both sides by 2.
#(cancel(2) x)/cancel(2) < 2/2#
#rArrx < 1" is the solution"#
