First, expand the term within parenthesis by multiplying by the term outside the parenthesis:
#(color(red)(-2) * x) + (color(red)(-2) * -4) <= -10#
#-2x + (+8) <= - 10#
#-2x + 8 <= - 10#
Next we can subtract #color(red)(8)# from each side of the inequality to isolate the #x# term while keeping the inequality balanced:
#-2x + 8 - color(red)(8) <= - 10 - color(red)(8)#
#-2x + 0 <= - 18#
#-2x <= -18#
New, we can solve for #x# by dividing each side of the inequality by #color(blue)(-2)# which will also keep the inequality balanced.
However, because this is an inequality and we are multiplying or dividing the inequality by a negative term we must also reverse the inequality:
#(-2x)/color(blue)(-2) color(red)(>=) (-18)/color(blue)(-2)#
#(color(blue)(cancel(color(black)(-2)))x)/cancel(color(blue)(-2)) color(red)(>=) 9#
#x >= 9#
