How do you solve $2 (x + 4) - x = 15$ $2( x + 4) - x = 15$ ?

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Answer 1 · 2017-03-11T18:27:55

See the entire solution process below:

First, expand the terms within parenthesis by multiplying each term within the parenthesis by $2$ $color(red)(2)$ :

$2 (x + 4) - x = 15$ $color(red)(2)(x + 4) - x = 15$

$(2 \times x) + (2 \times 4) - x = 15$ $(color(red)(2) xx x) + (color(red)(2) xx 4) - x = 15$

$2 x + 8 - x = 15$ $2x + 8 - x = 15$

Next, group and combine like terms on the left side of the equation:

$2 x - x + 8 = 15$ $2x - x + 8 = 15$

$2 x - 1 x + 8 = 15$ $2x - 1x + 8 = 15$

$(2 - 1) x + 8 = 15$ $(2 - 1)x + 8 = 15$

$1 x + 8 = 15$ $1x + 8 = 15$

$x + 8 = 15$ $x + 8 = 15$

Now, subtract $8$ $color(red)(8)$ from each side of the equation to solve for $x$ $x$ while keeping the equation balanced:

$x + 8 - 8 = 15 - 8$ $x + 8 - color(red)(8) = 15 - color(red)(8)$

$x + 0 = 7$ $x + 0 = 7$

$x = 7$ $x = 7$

How do you solve 2(x+4)−x=152( x + 4) - x = 15?