How do you solve #20= 6( d - 87) - 52#?

Question

352 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-09-04T23:38:29

#d = 99#

#20 = 6(d - 87) - 52#

Expand the bracket

#20 = 6d - 522 - 52#

#20 = 6d - 574#

Collect like terms

#20 + 574 = 6d#

#594 = 6d#

#594/6 = d#

#99 = d#

#:. d = 99#