How do you solve #20 + 7x - 35= 48#?

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Answer 1 · 2017-12-08T11:39:24

See a solution process below:

First, group and combine like terms on the left side of the equation. In this problem the common terms are the constants:

#color(red)(20) + 7x - color(red)(35) = 48#

#color(red)(20) - color(red)(35) + 7x = 48#

#-15 + 7x = 48#

Next, add #color(red)(15)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#-15 + color(red)(15) + 7x = 48 + color(red)(15)#

#0 + 7x = 63#

#7x = 63#

Now, divide each side of the equation by #color(red)(7)# to solve for #x# while keeping the equation balanced:

#(7x)/color(red)(7) = 63/color(red)(7)#

#(color(red)(cancel(color(black)(7)))x)/cancel(color(red)(7)) = 9#

#x = 9#