How do you solve #22^ { 2} + b ^ { 2} = 25^ { 2}#?

1 Answer
Jim G.
Jan 30, 2018

#b=+-sqrt141#

Explanation:

#"isolate "b^2" by subtracting "22^2" from both sides"#

#cancel(22^2)cancel(-22^2)+b^2=25^2-22^2#

#rArrb^2=625-484=141#

#color(blue)"take the square root of both sides"#

#rArrsqrt(b^2)=+-sqrt141larrcolor(blue)"note plus or minus"#

#rArrb=+-sqrt141#

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