How do you solve #22- ( 2x + 3) \leq 2( x + 2) + x#?

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Answer 1 · 2017-03-31T19:00:32

#x>=3#

#22-(2x+3)<=2(x+2)+x#

expand brackets:

#22-2x-3<=2x+4+x#

#19-2x<=3x+4#
#-2x+19<=3x+4#

subtract #3x#:
#-5x+19<=4#

subtract #19#:
#-5x<=-15#

divide by #-5#:
#x>=3#
(NB: when multiplying or dividing by a negative number, the inequality sign reverses)