Question

How do you solve `24x ^ { 2} + 100x + 16= 0`?

Answer 1

`x_1=-4` and `x_2=-1/6`

Explanation:

`24x^2+100x+16=0`

`Delta=100^2-4*24*16=8464=92^2`

Hence `x_1=(-100-92)/(2*24)=(-192)/48=-4` and `x_2=(-100+92)/(2*24)=(-8)/48=-1/6`