How do you solve #25 = 7 + 3k- 12#?

2 Answers
Aug 21, 2016

#k=10#

Explanation:

#25=7+3k-12#

or

#3k-5=25#

or

#3k=25+5#

or

#3k=30#

or

#k=30/3#

or

#k=10#

Aug 21, 2016

k = 10

Explanation:

Write the equation as follows, so that the k term is on the left side.

#3k+7-12=25rArr3k-5=25#

add 5 to both sides to isolate k term on left.

#rArr3k-cancel(5)+cancel(5)=25+5rArr3k=30#

now divide both sides by 3 to obtain k.

#(cancel(3)^1 k)/cancel(3)^1=cancel(30)^10/cancel(3)^1rArrk=10#