How do you solve #25 = 7 + 3k- 12#?
2 Answers
Aug 21, 2016
Explanation:
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Aug 21, 2016
k = 10
Explanation:
Write the equation as follows, so that the k term is on the left side.
#3k+7-12=25rArr3k-5=25# add 5 to both sides to isolate k term on left.
#rArr3k-cancel(5)+cancel(5)=25+5rArr3k=30# now divide both sides by 3 to obtain k.
#(cancel(3)^1 k)/cancel(3)^1=cancel(30)^10/cancel(3)^1rArrk=10#