How do you solve #25x + 74= 23x + 9#?

1 Answer
Jun 2, 2017

See a solution process below:

Explanation:

First, subtract #color(red)(74)# and #color(blue)(23x)# from each side of the equation to solve for isolate the #x# term while keeping the equation balanced:

#-color(blue)(23x) + 25x + 74 - color(red)(74) = -color(blue)(23x) + 23x + 9 - color(red)(74)#

#(-color(blue)(23) + 25)x + 0 = 0 - 65#

#2x = -65#

Next, divide each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#(2x)/color(red)(2) = -65/color(red)(2)#

#(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = -65/2#

#x = -65/2#