Question

How do you solve `26- 2x = 4x`?

Answer 1

See a solution process below:

Explanation:

First, add `color(red)(2x)` to each side of the equation to isolate the `x` term while keeping the equation balanced:

`26 - 2x + color(red)(2x) = 4x + color(red)(2x)`

`26 - 0 = (4 + color(red)(2))x`

`26 = 6x`

Now, divide each side of the equation by `color(red)(6)` to solve for `x` while keeping the equation balanced:

`26/color(red)(6) = (6x)/color(red)(6)`

`(13 xx 2)/color(red)(3 xx 2) = (color(red)(cancel(color(black)(6)))x)/cancel(color(red)(6))`

`(13 xx color(red)(cancel(color(black)(2))))/color(red)(3 xx color(blue)(cancel(color(red)(2)))) = x`

`13/3 = x`

`x = 13/3`