How do you solve #(26-y)/5 = 4#?

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Answer 1 · 2015-11-22T13:23:08

#color(green)(y=6)#

Given: #(26-y)/5=4#

Write as #color(brown)(1/5 times (26-y)=4)#

#color(green)("Multiply both sides by "color(blue)(5)" giving:")#

#color(brown)( color(blue)(5 times ) 1/5(26-y)=color(blue)(5 times )4)#

#color(blue)(5)/5 times (26-y)= 20#

But #5/5 = 1# giving:

#1 times (26-y)=20#

#color(green)("Subtract "color(blue)(26)" from both sides:")#

#color(brown)((26-y)color(blue)(-26)=(20) color(blue)(-26)#

#-y=-6#

Multiply both sides by (-1)

#color(green)(y=6)#