First, expand the terms in parenthesis on the right side of the equation by multiplying each term within the parenthesis by the term outside the parenthesis:
#27 + 3x = color(red)(6)(-3 + 8x)#
#27 + 3x = (color(red)(6) xx -3) + (color(red)(6) xx 8x)#
#27 + 3x = -18 + 48x#
Next, subtract #color(red)(3x)# and add #color(blue)(18)# to each side of the equation to isolate the #x# term while keeping the equation balanced:
#27 + color(blue)(18) + 3x - color(red)(3x) = -18 + color(blue)(18) + 48x - color(red)(3x)#
#45 + 0 = 0 + (48 - color(red)(3))x#
#45 = 45x#
Now, divide each side of the equation by #color(red)(45)# to solve for #x# while keeping the equation balanced:
#45/color(red)(45) = (45x)/color(red)(45)#
#1 = (color(red)(cancel(color(black)(45)))x)/cancel(color(red)(45))#
#1 = x#
#x = 1#
