How do you solve $27 = x^{\frac{2}{3}}$ $27=x^(2/3)$ ?

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Answer 1 · 2018-03-13T20:23:59

Raise to the power of $\frac{2}{3}$ $2/3$ hence

$27^{\frac{3}{2}} = {(x^{\frac{2}{3}})}^{\frac{3}{2}}$ $27^(3/2)=(x^(2/3))^(3/2)$

$27^{\frac{3}{2}} = x$ $27^(3/2)=x$

$x = {(27^{\frac{1}{2}})}^{3}$ $x = (27^(1/2) )^3$

$x = {(3 \sqrt{3})}^{3} = 81 \sqrt{3}$ $x = (3sqrt(3))^3 = 81sqrt(3)$

How do you solve 27=x^(2/3)27=x2327=x^(2/3)?