How do you solve #27= x ^ { \frac { 3} { 2} }#?

1 Answer
Nov 17, 2016

#x=9#

Explanation:

#x^(3/2)=27#

Take #log_3# in both sides of the equation, you get

#log_3(x^(3/2))=log_3(27)#

Using the power property of logarithms #log_b(a^p)=p*log_b(a)#, expand the left hand side of the equation. Simplify the right hand side also to get

#3/2log_3(x)=3#

Multiply by #2/3# on both sides of the equation

#cancel(2/3)*cancel(3/2)log_3(x)=3*2/3 -> log_3(x)=2#

Convert #log_3(x)=2# to exponential form

#log_3(x)=2->3^2=x#

So #x=9# is your final answer