How do you solve #-272= 8- 7( 5n + 5)#?

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Answer 1 · 2018-04-04T16:53:42

#n = 7#

Here's how I did it:

#-272 = 8 - 7(5n + 5)#

First, let's subtract #8# from both sides of the equation:
#-280 = -7(5n + 5)#

Now we use the distributive property to "distribute" or multiply the #-7# to everything in its parenthesis:
#-280 = -35n - 35#

Now we add #35# to both sides of the equation:
#-245 = -35n#

Finally we divide both sides by #-35# to solve for #n#:
#n = 7#

Hope this helps!