How do you solve #(2a^2b)^3 -: (4a^4b)#?

Question

1954 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-05T13:04:50

#2a^2b^2#

#(2a^2b)^3 rarr# First let's distribute out the exponent #3#

#2^3a^6b^3#

#(2^3a^6b^3)/(4a^4b)#

Remember: #a^b/a^c=a^(b-c)#

#(8a^6b^3)/(4a^4b)#

#2a^(6-4)b^(3-1)#

#2a^2b^2#