How do you solve #(2c + 1) ( c - 5) = 0#?
1 Answer
Mar 27, 2017
#2c^2 -9c -5
Explanation:
Using the FOIL method (First Outside Inside Last)
Multiply 2c by c, you get #2c^2
Then multiply the outsides, -5 by 2c, you get -10c
Next multiply the insides, c by 1 you get c (or 1c)
Lastly, multiply the last, -5 by 1, you get -5
Write them down you would have
#2c^2 -10c + c -5
Add like terms, you get
#2c^2 -9c -5