# How do you solve 2e^x-1=0?

Jun 11, 2018

$x = \ln \left(\frac{1}{2}\right)$

#### Explanation:

$2 {e}^{x} - 1 = 0$

$2 {e}^{x} = 1$

${e}^{x} = \frac{1}{2}$

Take natural log of both sides:
$\ln {e}^{x} = \ln \left(\frac{1}{2}\right)$

$x = \ln \left(\frac{1}{2}\right)$