How do you solve #2k = - 3( k - 1) + 7#?

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Answer 1 · 2017-02-05T21:27:09

See the entire solution process below:

First, expand the terms within parenthesis on the right side of the equation:

#2k = -3(k - 1) + 7#

#2k = (-3 xx k) + (-3 xx - 1) + 7#

#2k = -3k + 3 + 7#

#2k = -3k + 10#

Next, add #color(red)(3k)# to each side of the equation to isolate the #k# term while keeping the equation balanced:

#color(red)(3k) + 2k = color(red)(3k) - 3k + 10#

#5k = 0 + 10#

#5k = 10#

Now, divide each side of the equation by #color(red)(5)# to solve for #k# while keeping the equation balanced:

#(5k)/color(red)(5) = 10/color(red)(5)#

#(color(red)(cancel(color(black)(5)))k)/cancel(color(red)(5)) = 2#

#k = 2#