How do you solve #2log_5 x = 250#?

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Answer 1 · 2016-05-29T20:39:28

#x=5^125# as an exact value

By calculator this is approximately #2.351xx10^87# to 3 decimal places

Consider #" "log_10(x)=y#

This is another way of writing:#" "10^y=x#

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Divide both sides by 2

# " " log_5x=125#

Comparing to my example above this can be written as:

#" "x=5^125#