How do you solve #-2log_8(x+1) = - 8#?

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Answer 1 · 2017-06-25T00:30:54

#x = 4095#

We have: #- 2 log_(8)(x + 1) = - 8#

Dividing both sides of the equation by #- 2#:

#Rightarrow log_(8)(x + 1) = 4#

Using the laws of logarithms:

#Rightarrow x + 1 = 8^(4)#

#Rightarrow x + 1 = 4096#

Subtracting #1# from both sides:

#therefore x = 4095#