# How do you solve 2m - 3n = 6 and m = 3 - 2n using substitution?

Mar 15, 2016

The solution for the system of equations is:
color(blue)(n=0
color(blue)(m=3

#### Explanation:

 2m−3n=6 ..............equation $\left(1\right)$
color(green)( m=3−2n ).................equation $\left(2\right)$

Substituting equation $2$ in $1$:

2m−3n=6

2 * color(green)( (3−2n ))−3n=6

6 -4n−3n=6

$6 - 7 n = 6$

$6 - 6 = 7 n$

$7 n = 0$

$n = \frac{0}{7}$

color(blue)(n=0

finding the value of $m$ by substituting the value of $n$ in equation $2$:

m=3−2n

m=3−2 * 0

$m = 3 - 0$

color(blue)(m=3