How do you solve #2m + 6( 2m - 4) < 8( m - 8) - 8#?

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Answer 1 · 2016-09-27T00:00:33

#m <-6#

#2m + 6(2m - 4) < 8(m - 8) - 8#

Because of the order of equations, you distribute the 6 through the first set of parenthesis and the 8 through the second set

#2m + 12m -24 < 8m -64 -8#

Then, combine like terms on the left and right side of the inequality
#14m - 24 < 8m - 72#

Add 24 on both sides of the inequality
#14m< 8m-48#

Subtract 8m on both sides of the inequality
#6m < - 48#

Isolate the variable by dividing both sides by 6
#m<-6#