How do you solve #(2n+3)/4 = (5n-1)/6#?

1 Answer
Feb 23, 2016

#x=11/4#

Explanation:

#color(blue)((2n+3)/4=(5n-1)/6#

Cross multiply #color(orange)(If,a/b=c/d,Then,ad=bc#

#rarr6(2n+3)=4(5n-1)#

Use distributive property #color(red)(a(b+c)=ab+ac#

#rarr12n+18=20n-4#

Subtract #12n# both sides

#rarr18=8n-4#

Rearrange the equation

#rarr8n-4=18#

Add #4# both sides

#rarr8n=18+4#

#rarr8n=22#

Divide both sides by #8#

#rarr(cancel8n)/cancel8=(22)/8#

#rArrcolor(green)(x=22/8=11/4#