How do you solve #2s + 1> - 9#?

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Answer 1 · 2017-11-28T03:21:50

See a solution process below:

First, subtract #color(red)(1)# from each side of the inequality to isolate the #s# term while keeping the inequality balanced:

#2s + 1 - color(red)(1) > -9 - color(red)(1)#

#2s + 0 > -10#

#2s > -10#

Now, divide each side of the inequality by #color(red)(2)# to solve for #s# while keeping the inequality balanced:

#(2s)/color(red)(2) > -10/color(red)(2)#

#(color(red)(cancel(color(black)(2)))s)/cancel(color(red)(2)) > -5#

#s > -5#