How do you solve #2s+s+12=132#?

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Answer 1 · 2018-03-06T02:00:46

#s=40#

#2s+s+12=132#

#3s+12=132#

#3s=120#

#s=40#

Answer 2 · 2018-03-06T02:01:41

Simplify by moving all like terms to one side:

#2s+s=132-12#

#3s=120#

#s=40#

Answer 3 · 2018-03-06T02:05:51

#s=40#

Combine like terms:

#2s + s = 3s#

Changing the equation to #3s+12=132#

Now you work backwards using #"PEMDAS"#
#"(Parenthesis, Exponent, Multiply, Divide, add then subtract.)"#

Which means subtract #12# from #132# since it would be the last step if we were using PEMDAS.

#132-12= 120#

#3s= 120#

and using division to isolate and get one #s#, you get #40#.