# How do you solve 2sin^3X-sin^2X-2SinX+1=0? I don't get how you get the 270.

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#2sin^3x-sin^2x-2sinx+1=0# for the interval #[0,2pi)#

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Let's factor:

Set each equal to zero and solve for

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So

when

Hence

when

when

Again

when

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Factorize

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