How do you solve #(2x-1)(1+2x+4x^2) = 8x^3-x#?

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Answer 1 · 2017-09-25T18:26:12

Perform the multiplication on the left.
Combine like terms.

Given: #(2x-1)(1+2x+4x^2) = 8x^3-x#

Perform the multiplication on the left:

#2x(1+2x+4x^2)-1(1+2x+4x^2) = 8x^3-x#

#2x+4x^2+8x^3-1-2x-4x^2 = 8x^3-x#

Combine like terms:

#-1 = -x#

#x = 1#