How do you solve #2x + 1> - 11#?

1 Answer
Jim G.
Dec 20, 2016

#x> -6#

Explanation:

Leave the 2x on the left side of the inequality and subtract 1 from both sides.

#2xcancel(+1)cancel(-1)> -11-1#

#rArr2x> -12#

To solve for x, divide both sides by 2

#(cancel(2) x)/cancel(2)> (-12)/2#

#rArrx> -6" is the solution"#

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