How do you solve $(2 x - 1) + 50 + (3 x + 5) = 180$ $(2x - 1) + 50+ ( 3x + 5) = 180$ ?

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How do you solve $(2 x - 1) + 50 + (3 x + 5) = 180$ $(2x - 1) + 50+ ( 3x + 5) = 180$ ?

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Answer 1 · 2017-11-13T06:24:35

$x = 26.2$ $x = 26.2$

Explanation:

$(2 x - 1) + 50 + (3 x + 5) = 180$ $(2x - 1) + 50 + (3x + 5) = 180$

Simplifying the Brackets first..

$2 x - 1 + 50 + 3 x + 5 = 180$ $2x - 1 + 50 + 3x + 5 = 180$

Collecting like terms..

$2 x + 3 x - 1 + 50 + 5 = 180$ $2x + 3x - 1 + 50 + 5 = 180$

$5 x + 54 = 180$ $5x + 54 = 180$

$5 x = 180 - 54$ $5x = 180 - 54$

$5 x = 126$ $5x = 126$

$x = \frac{126}{5}$ $x = 126/5$

$x = 26.2$ $x = 26.2$

Answer 2 · 2017-11-13T06:32:36

$x = \frac{126}{5}$ $x=126/5$

Explanation:

Given -

$(2 x - 1) + 50 + (3 x + 5) = 180$ $(2x-1)+50+(3x+5)=180$

Remove the brackets.

[To remove the bracket you must multiply the signs inside the bracket with the sign preceding the bracket. ]

$2 x - 1 + 50 + 3 x + 5 = 180$ $2x-1+50+3x+5=180$

$5 x + 54 = 180$ $5x+54=180$

$5 x + 54 - 54 = 180 - 54$ $5x+54-54=180-54$

$5xcancel(+54)cancel(-54)=126$

$(5x)/5=126/5$

$(cancel5x)/cancel5=126/5$

$x=126/5$

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How do you solve $(2 x - 1) + 50 + (3 x + 5) = 180$ $(2x - 1) + 50+ ( 3x + 5) = 180$ ?

2 Answers

Explanation:

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How do you solve (2x - 1) + 50+ ( 3x + 5) = 180(2x−1)+50+(3x+5)=180(2x - 1) + 50+ ( 3x + 5) = 180?

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How do you solve $(2 x - 1) + 50 + (3 x + 5) = 180$ $(2x - 1) + 50+ ( 3x + 5) = 180$ ?