How do you solve #2x^2+11=131# by square roots?

1 Answer
Dec 23, 2016

Take the #11# to the other side first:

Explanation:

#->2x^2=131-11=120#

#->x^2=120/2=60#

#->x_(1,2)=+-sqrt60=+-2sqrt15#

Note!
There are two solutions, as #-sqrt60# will also be #60# when squared. This is often forgotten.