Question

How do you solve `2x^{2}+19x-10=0`?

Answer 1

`x= -10 or +1/2`

Explanation:

`2x^2+19x-10=0`

`(2x-1)(x+10)=0`

`:.` either `(x+10) = 0 -> x=-10`

or `(2x-1)=0 -> x=+1/2`