Question

How do you solve `2x ^ { 2} - 28x + 37= - 11`?

Answer 1

`x_1=2` and `x_2=12`

Explanation:

`2x^2-28x+37=-11`

`2x^2-28x+48=0`

`x^2-14x+24=0`

`(x-2)*(x-12)=0`

Hence `x_1=2` and `x_2=12`