How do you solve #2x^2 + 4x = -3#?
2 Answers
Dec 2, 2016
#x=-1+-isqrt(-1)/2#
Explanation:
Given -
#2x^2+4x=-3#
Divide by 2
#(2x^2)/2+(4x)/2=(-3)/2#
#x^2+2x=(-3)/2#
take half of the coefficient of
#x^2+2x+1=(-3)/2+1#
#(x+1)^2=(-3+2)/2=(-1)/2#
Taking square on both sides
#x+1=sqrt(-1)/2#
#x=-1+-isqrt(-1)/2#
Dec 2, 2016
Explanation:
Solve:
Add
Quadratic Formula
Substitute the given values into the formula and solve for
Simplify.
Simplify.