How do you solve -2x^2-4x+30=02x24x+30=0 by completing the square?

1 Answer
Feb 4, 2016

x=3 or x=-5x=3orx=5
(see below for solution method)

Explanation:

Given:
color(white)("XXX")-2x^2-4x+30=0XXX2x24x+30=0

Before completing the square, simplify by dividing everything (on both sides) by (-2)(2)
color(white)("XXX")x^2+2x-15=0XXXx2+2x15=0

Move the constant to the right side (by adding 1515 to both sides)
color(white)("XXX")color(blue)(x^2+2x)=15XXXx2+2x=15

Now to complete the square
[ (color(white)("XXXXXX")"Since "(x+a)^2 = color(blue)(x^2+2ax)+a^2), (color(white)("XXXXXX")"If "color(blue)(x^2+2x)" are the first two terms of a squared binomial"), (color(white)("XXXXXX")"Then "a=1" in the general expansion"), (color(white)("XXXXXX")"and we will need to add "color(red)(1)" to both sides"), (color(white)("XXXXXX")"to get a squared binomial on the left side:"), (color(white)("XXX")color(blue)(x^2+2x)color(red)(+1) = 15color(red)(+1)), (" "), (color(white)("XXX")"Re-writing as a squared binomial (and a simplified constant on the right side):"), (color(white)("XXX")(x+1)^2=16) :}

Take the square root of both sides:
color(white)("XXX")x+1=+-4 (don't forget both roots of 16)

Subtract 1 from both sides:
color(white)("XXX")x=3 or x=-5