How do you solve #2x ^ { 2} - 6x - 36= 0#?

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Answer 1 · 2016-11-29T16:19:41

#x=-3# or #x=6#

#2x^2-6x-36=0#

Factorise.

#2x^2-12x+6x-36=0#

#2x(x-6)+6(x-6)=0#

#(2x+6)(x-6)=0#

#2x+6=0# or #x-6=0#

#2x=-6# or #x=6#

Divide both sides of the first equation by #2#.

#x=-3# or #x=6#