Question

How do you solve `2x-28=4x-36`?

Answer 1

See a solution process below:

Explanation:

First, subtract `color(red)(2x)` and add `color(blue)(36)` to each side of the equation to isolate the `x` term while keeping the equation balanced:

`2x - color(red)(2x) - 28 + color(blue)(36) = 4x - color(red)(2x) - 36 + color(blue)(36)`

`0 + 8 = (4 - color(red)(2))x - 0`

`8 = 2x`

Now, divide each side of the equation by `color(red)(2)` to solve for `x` while keeping the equation balanced:

`8/color(red)(2) = (2x)/color(red)(2)`

`4 = (color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2))`

`4 = x`

`x = 4`