How do you solve #-2x ^ { 3} = 54#?

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Answer 1 · 2017-01-28T18:22:21

See the entire solution process below:

First, divide each side of the equation by #color(red)(-2)# to isolate the #x# term and keep the equation balanced:

#(-2x^3)/color(red)(-2) = 54/color(red)(-2)#

#(color(red)(cancel(color(black)(-2)))x^3)/cancel(color(red)(-2)) = -27#

#x^3 = -27#

Now, take the cubed root of each side of the equation to solve for #x# while keeping the equation balanced:

#root(color(red)(3))(x^3) = root(color(red)(3))(-27)#

#x = -3#