How do you solve #2x - 3+ 6x = 77#?

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Answer 1 · 2017-05-14T04:23:01

See a solution process below:

First, group and combine like terms on the left side of the equation:

#2x - 3 + 6x = 77#

#2x + 6x - 3 = 77#

#(2 + 6)x - 3 = 77#

#8x - 3 = 77#

Next, add #color(red)(3)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#8x - 3 + color(red)(3) = 77 + color(red)(3)#

#8x - 0 = 80#

#8x = 80#

Now, divide each side of the equation by #color(red)(8)# to solve for #x# while keeping the equation balanced:

#(8x)/color(red)(8) = 80/color(red)(8)#

#(color(red)(cancel(color(black)(8)))x)/cancel(color(red)(8)) = 10#

#x = 10#