How do you solve $2 x - 3 + 6 x = 77$ $2x - 3+ 6x = 77$ ?

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Answer 1 · 2017-05-14T04:23:01

See a solution process below:

First, group and combine like terms on the left side of the equation:

$2 x - 3 + 6 x = 77$ $2x - 3 + 6x = 77$

$2 x + 6 x - 3 = 77$ $2x + 6x - 3 = 77$

$(2 + 6) x - 3 = 77$ $(2 + 6)x - 3 = 77$

$8 x - 3 = 77$ $8x - 3 = 77$

Next, add $3$ $color(red)(3)$ to each side of the equation to isolate the $x$ $x$ term while keeping the equation balanced:

$8 x - 3 + 3 = 77 + 3$ $8x - 3 + color(red)(3) = 77 + color(red)(3)$

$8 x - 0 = 80$ $8x - 0 = 80$

$8 x = 80$ $8x = 80$

Now, divide each side of the equation by $8$ $color(red)(8)$ to solve for $x$ $x$ while keeping the equation balanced:

$\frac{8 x}{8} = \frac{80}{8}$ $(8x)/color(red)(8) = 80/color(red)(8)$

$(color(red)(cancel(color(black)(8)))x)/cancel(color(red)(8)) = 10$

$x = 10$

How do you solve 2x - 3+ 6x = 772x−3+6x=772x - 3+ 6x = 77?