How do you solve $-2x+3<=9$ ?

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Answer 1 · 2016-07-16T10:24:57

$x>=6$

The objective is to get $x$ on its own on one side of the inequality sign and everything else on the other.

$color(brown)("Making the "x" term positive")$

Multiply by (-1)

$+2x-3>=9 larr" notice that the "<=" is now ">=$

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$color(brown)("Isolating the "x" term")$

Add 3 to both sides

$+2x-3+3>=9+3$

$2x>=12$

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$color(brown)("Isolating "x)$

Divide both sides by 2

$2/2xx x>=12/2$

$x>=6$

How do you solve -2x+3<=9-2x+3<=9?