How do you solve #2x^3 - x^2 + 2x - 1 = 0#?
1 Answer
Jan 12, 2016
Factor by grouping, then identify zeros:
#x=1/2# ,#x=i# ,#x=-i#
Explanation:
Factor by grouping:
#2x^3-x^2+2x-1#
#=(2x^3-x^2)+(2x-1)#
#=x^2(2x-1)+1(2x-1)#
#=(x^2+1)(2x-1)#
This has one Real zero, namely
