How do you solve #2x-3<x+ 2<=3x+5#?

1 Answer
Binayaka C.
Jul 20, 2017

Solution : # -3/2 <= x <5# , in interval notation: #[-3/2,5)#

Explanation:

#2x-3 < x+2 <= 3x+5 #

1) #2x-3 < x+2 or 2x-x < 2 +3 or x < 5#

2) #x+2 <= 3x+5 or x -3x <= 5-2 or -2x <= 3 # or

# -x <= 3/2 or x >= -3/2#

Solution : # -3/2 <= x <5# , in interval notation: #[-3/2,5)# [Ans]

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