#2x + 3y = 6#
#x + y = 3#
Let's solve for #x# in the second equation
#x = 3 - y#
Now let's plug #(3-y)# in for #x# in the first equation
#2(3-y) + 3y = 6#
#6 - 2y + 3y = 6#
#y = 0#
#* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *#
Now we have #y#, let's find #x#
#x = 3 - y#
#x = 3 - 0#
#x = 3#
#* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *#
Let's double check our work and use our #x# and #y# values in the first equation and solve it. If our numbers are correct, the equation should equal #6#
#2(3) + 3(0)
#6 + 0#
#6 = 6#! We were right!
