2x + 3y = 62x+3y=6
x + y = 3x+y=3
Let's solve for xx in the second equation
x = 3 - yx=3−y
Now let's plug (3-y)(3−y) in for xx in the first equation
2(3-y) + 3y = 62(3−y)+3y=6
6 - 2y + 3y = 66−2y+3y=6
y = 0y=0
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Now we have yy, let's find xx
x = 3 - yx=3−y
x = 3 - 0x=3−0
x = 3x=3
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Let's double check our work and use our xx and yy values in the first equation and solve it. If our numbers are correct, the equation should equal 66
#2(3) + 3(0)
6 + 06+0
6 = 66=6! We were right!
