How do you solve #2x + 4+ 3x = 29#?

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Answer 1 · 2017-11-03T12:36:07

See a solution process below:

First, group and combine like terms on the left side of the equation:

#2x + 3x + 4 = 29#

#(2 + 3)x + 4 = 29#

#5x + 4 = 29#

Next, subtract #color(red)(4)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#5x + 4 - color(red)(4) = 29 - color(red)(4)#

#5x + 0 = 25#

#5x = 25#

Now, divide each side of the equation by #color(red)(5)# to solve for #x# while keeping the equation balanced:

#(5x)/color(red)(5) = 25/color(red)(5)#

#(color(red)(cancel(color(black)(5)))x)/cancel(color(red)(5)) = 5#

#x = 5#