Question

How do you solve `2x - 4y = 32` and `8x - 8y = 96`?

Answer 1

Notice that we're gonna solve for `x` first because if we solve for `x` in the first equation... we can factorize and get `x` without doing any kind of multiplication or something

Explanation:

We're gonna solve for `x` first

First equation
`2x-4y=32`
`2x=32+4y`
`x=(32+4y)/2`
`x=32/2+(4y)/2`
`x=16+2y`

Second equation
`8x-8y =96`
Factorize
`8(x-y)=96`
Transfer the 8 and put value of `x`
`16+2y-y=96/8`
`16+y=12`
`y=12-16`
`color(red)(y=-4)`
Get the value of `x`
`x=16+2y`
`x=16+2xx-4`
`x=16+(-8)`
`color(red)(x=8)`