How do you solve #2x - 5< 3x + 2< 4x - 3#?

1 Answer
Jul 5, 2017

Solution : #x >5 # In interval notation: #(-7,oo) nn (5 ,oo) or (5,oo)#

Explanation:

1) #2x -5 < 3x +2 or 2x -3x < 5 +2 or -x <7 or x > -7 or (-7,oo)#

2) # 3x +2 < 4x -3 or 3x -4x < -3 -2 or -x < -5 or x > 5 or (5,oo)#

#x>5# satisfies both (1) and (2) or #(-7,oo) nn (5 ,oo) #

Solution : #x >5 # In interval notation: #(-7,oo) nn (5 ,oo) # or #(5,oo)#

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