How do you solve $2 x - 5 + x = 17$ $2x-5+x=17$ ?

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Answer 1 · 2017-11-29T03:20:02

See a solution process below:

First, add $5$ $color(red)(5)$ to each side of the equation to isolate the $x$ $x$ terms while keeping the equation balanced:

$2 x - 5 + 5 + x = 17 + 5$ $2x - 5 + color(red)(5) + x = 17 + color(red)(5)$

$2 x - 0 + x = 22$ $2x - 0 + x = 22$

$2 x + x = 22$ $2x + x = 22$

Next, combine like terms on the left side of the equation:

$2 x + x = 22$ $2x + x = 22$

$2 x + 1 x = 22$ $2x + 1x = 22$

$(2 + 1) x = 22$ $(2 + 1)x = 22$

$3 x = 22$ $3x = 22$

Now, divide each side of the equation by $3$ $color(red)(3)$ to solve for $x$ $x$ while keeping the equation balanced:

$\frac{3 x}{3} = \frac{22}{3}$ $(3x)/color(red)(3) = 22/color(red)(3)$

$(color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3)) = 22/3$

$x = 22/3$

How do you solve 2x-5+x=172x−5+x=172x-5+x=17?